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Peterson lost his wicket in the Shardul Thakur trap, see in the video

Shardul Thakur India vs South Africa Cape Town Test: The final match of the Test series between India and South Africa is taking place in Cape Town. India scored 223 in the first innings and 198 in the second innings. In reply, South Africa were bowled out for 210 in the first innings. Now playing second innings. At this point Keegan Peterson became a big problem for Team India. Playing with a stick. But India fast bowler Shardul Thakur was caught in his trap.

In the second innings of South Africa, Edin Markram and Dean Elgar opened. Markram was dismissed for a personal score of 16 runs. After his outing, Peterson reached the crease. He kept playing. He scored 82 off 113 balls. Petersen’s innings made South Africa much easier to target.

The pace of these players is more than ‘leopard’ and Team India cricketer tops the list of maximum catches.

Peterson was the head of the India team. It was hard to get him out. At this point skipper Virat Kohli gave over to Shardul. Shardul was dismissed in the second delivery of the 47th over. Peterson bowled, unable to understand Shardul’s ball.

IND vs SA 3rd Test: Rishabh Pant’s game-changing innings, with Team India changing the outcome of the match

Let us tell you that India won the first match of the Test series. But they lost in the second game. The decisive match of the Test series is now underway in Cape Town. This match is India’s fault. Now only a little charisma can win India.

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